The median of 111, 129, 143, 118, 120, 125, 170, 162 is | 12 | MEASURES OF DISPERSION (STATISTI...

Assertion : The median of the data 105, 103, 102, 107, 120, 124, 111 and 124 is 109 Reason : When the number of observations (n) is odd, then the median is the value of the ((n + 1)/(2))^(th) observation. If the number of observations (n) is even , then the median is the mean of the ((n)/(2))^(th) observation and the ((n)/(2) + 1)^(th) observation

Assertion : The range of the data 114, 115, 116, 118, 119, 125, 130, 141, 126, 116, 113, 118, 120, and 126, is 100 Reason : The difference between the highest and the lowest value of the data is called range

Given below are heights of 15 boys of a class measured in cm: 128, 144, 146, 143, 136, 142, 138, 129, 140, 152, 144, 140, 150, 142, 154. Find (a) The height of the tallest boy. (b) The height of the shortest boy. (c) The range of the given data. (d) The median height of the boys.

The median of the first 25 whole numbers is: A)10 B)12.5 C)15 D)12

Let the median and the mean deviation about the median of 7 observation 170, 125, 230, 190, 210, a, b be 170 and frac{205}{7} respectively. Then the mean deviation about the mean of these 7 observations is :

The weights in grams of 50 apples picked at random from a consignment are as follows 106, 107, 76, 82, 109, 107, 115, 93, 187, 195, 123, 125, 111, 92, 86, 70, 126, 68, 130 129, 139 119, 115, 128, 100, 186, 84, 99, 118, 204, 111, 141, 136 123, 90, 11 98, 110, 78, 90, 107, 81, 131, 75, 84, 104, 110, 80, 118, 82. Form the grouped frequency table by dividing the variable range into intervals of equal width, each corresponding to 70 gms in such a way that mid-value of the first class corresponds to 70 gms.

The heights of 7 students are given below (in cm) : 120, 126, 132.41, 121.52, 120.35, 132, 125. Find the median height of the students.