यदि `S ={1, 2, 3, ...,}, A ={x : x=2n, n in S}, B ={x : x =2n-1, n in S}` और `

If A={x:x=3^(n)-2n-1, n in N} and B={x:x = 4(n-1), n in N} . Then

Let A={x:x in N},B={x;x2n,n in N},C={x:x=2n-1,n in N}and,D={x:x is a prime natural number }. Find: A nn B

If ((1 +i)/(1 -i))^(x) =1 , then (A) x=2n+1 (B) x=4n (C) x=2n (D) x=4n+1, n in N.

Consider the following statements : S_(1) : If A={a} and B = {a, b, c}, then A in B . S_(2) : If n(A)=x, then n(P(A))=2^(x) . S_(3) : (AuuB)sube A . S_(4) : phi is subset of every set State, in order, whether S_(1), S_(2), S_(3), S_(4) and true or false

The area of the closed figure bounded by x=-1,x=2,a n d y={-x^2+2,xlt=1 2x-1,x >1a n dt h ea b s c i s s aa xi si s (16)/3s qdotu n i t s (b) (10)/3s qdotu n i t s (13)/3s qdotu n i t s (d) 7/3s qdotu n i t s

n + (n-1) x + (n-2) x ^ (2) + ....... + 2x ^ (n-2) + x ^ (n-1)

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

The area of the region bounded by x=0,y=0,x=2,y=2,ylt=e^x a n dygeq1nx is 6-41n2s qdotu n i t s (b) 41n2-2s qdotu n i t s 21n2-4s qdotu n i t s (d) 6-21n2s qdotu n i t s

Let" "S_(k)=( (1 ,k), (0 ,1) ), k in N .Then (S_(2))^(n)(S_(x))^(-1) (where n in N) is equal to: (S_(k))^(-1) denotes the inverse of matrix S_(k)