दिया गया v'=(1-v//c)vandv'=((1-v//c)v)/sqrt(1-v_(2)//c_(2)) किस मान के लिए v /सी, ये प्रश्न भिन्न हैं...

Given v'=(1-v//c)vandv'=((1-v//c)v)/sqrt(1-v_(2)//c_(2)) For what value v/c, these question differ by 10%

int (1-v) (dx)) / (1 + v + v ^ (2))

(V + 1) / (V (2V + 1)) dv = - (1) / (x) dx

If |vec(V)_(1)+vec(V)_(2)|=|vec(V)_(1)-vec(V)_(2)|and V_(2) is finite, then

If vec(v)_(1)+vec(v)_(2) is perpendicular to vec(v)_(1)-vec(v)_(2) , then

Find 3 -dimensional vectors vec v_ (1), vec v_ (2), vec v_ (3) satisfying vec v_ (1) * vec v_ (1) = 4, vec v_ (1) * vec v_ (2) = - 2, vec v_ (1) * vec v_ (3) = 6, vec v_ (2) * vec v_ (2) = 2, vec v_ (2) * vec v_ (3) = - 5, vec v_ (3) * vec v_ (3)

For any arbitrary motion in space, which of the following relations are true? (a) v_("average") = (1//2)(v(t_(1)) + v(t_(2))) (b) v_("average") = [r(t_(2))-r(t_(1)]//(t_(2)-t_(1)) (c) v(t) = v(0) + at (d) a_("average") = [v(t_(2))-v(t_(1))]//(t_(2)-t_(1)) The average stands for average of the quantity over time interval t_(1) to t_(2)

If V_(X)-V_(Y)=20V , find the value of C .

Evaluate : 1/3 int ( 1 + 2v ) / ( v^2 + v + 1 )dv