यदि x = sqrt( 2+ sqrt( 2+ sqrt( 2+ ................oo))) हो, तो x का एक मूल होगा | 12 | रेखिक त...

यदि x^(2)+2=0 हो तो x का मान होगा-

x=sqrt(12-sqrt(12-sqrt(12-....oo))) then x=

If x=sqrt(2-sqrt(2-sqrt(2))).......oo the value of x is given by

If x=sqrt(2+sqrt(2+sqrt(2+......*oo)) and )y=sqrt(2sqrt(2sqrt(2.........oo))) find x-y

(sqrt(x))^(2)-sqrt(x)-12=0

If x = sqrt(? + sqrt(?/?)) - sqrt(? -sqrt(?/?)) , then the value of (sqrt(?)−?)/(sqrt(?) +?) will be closest to: यदि x = sqrt(? + sqrt(?/?)) - sqrt(? -sqrt(?/?)) , तो (sqrt(?)−?)/(sqrt(?) +?) का निकटतम मान होगा:

If x=sqrt(2+sqrt(4+sqrt(4+sqrt(4+...oo)))) then the value of x^(2) is