একটি 10 ​​কেজি ওজনের বস্তু দুটি শক্তির অধীন হয় (নিউটনে) vec(F)_(1) = 16 হ্যাট (i) - 11 হ্যাট (j) একটি...

A 10 kg object is subjected to two forces ( in newton ) vec(F)_(1) = 16 hat (i) - 11 hat (j) and vec(F) _(2) = 8 hat (i) + 18 hat (j), , the magnitude of resulting acceleration in ms^(-2) will be

Find each of the following products: (a) 3 xx (-1) (b) (-1) xx 225 (c) (-21) xx (-30) (d) (-316) xx (-1) (e) (-15 xx 0 xx (-18) (f) (-12) xx (-11) xx (10) (g) 9 xx (-3) xx (-6) (h) (-18) xx (-5) xx (-4) (i) (-1) xx (-2) xx (-3) xx 4 (j) (-3) xx (-6) xx (-2) xx (-1)

Give the order of the following : (a) 1 (b) 1000 (c ) 499 (d) 500 (e) 501) (f) 1 AU (1.496 xx 10^(11) m) (g) 1 Å (10(-10)m ) (h) Speed of light (3.00 xx 10^(8) m//s) (i) Gravitational constant (6.67 xx 10^(-11) N-m^(2)//kg^(2)) (j) Avogadro constant (6.02 xx 10^(23) mol^(-1)) (k) Planck's constant (6.63 xx 10^(-34) J-s) (l) Charge on electron (1.60 xx 10^(-19) C) (m) Radius of H - atom (5.29 xx 10^(-11)m) (n) Atmospheric pressure (1.01 xx 10^(5) Pa) (o) Mass of earth (5.98 xx 10^(24)kg) (p) Mean radius of earth (6.37 xx 10^(6)m)

An observer O_(1) standing on ground finds that momentum of a projectile of mass 2 kg changes with time as vec(P)_(01) =(4that (i) + 20 t hat(k))kg m//s Acceleration due to gravity is vec(g)=(10 hat(k))m//s^(2) and there is a wind blowing in horizontal direction. Another observer O_(2) driving a car observes that momentum of the same projectile changes with time as - vec(P)_(02)=(8t hat(i)-16 hat(t) hat(j)+20 t hat(k))kg m//s . Find the acceleration of the car at t = (1)/(8) s

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N If the coordinates of the particle at t = 0 are (2 m, 1 m, 0), coordinates at a time t = 3 T, where T is the time period of circular component of motion. will be (take pi = 3.14 )

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N Motion of charged particle will be along a helical path with

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N Angular frequency of rotation of particle, also called the cyclotron frequency' is

Given four forces : vec F_1 = 3 hat i - hat j + 9 hat k vec F_2 = 2 hat i - 2 hat j + 16 hat k vec F_3 = 9 hat i + hat j + 18 hat k vec F_4= hat i + 2 hat j - 18 hat k If all these forces act on a particle at rest at the origin of a coordinate system, then identify the plane in which the particle would begin to move ?

A particle,in equilibrium,is subjected to four forces vec F_(1),vec F_(2),vec F_(3) and vec F_(4)vec F_(1)=-10hat k,vec F_(2)=u((4)/(13)hat i-(12)/(13)hat j+(3)/(13)hat k),vec F_(3)=v(-(4)/(13)hat i-(12)/(13)hat j+(3)/(13)hat k),vec F_(4)=w(cos thetahat i+sin thetahat j) then find the values of u,v and w

Three forces (vec(F)_(1), vec(F)_(2), vec(F)_(3)) are acting an a particle moving vertically up with constant speed. Two force vec(F)_(1)=-10hat(j)N , and vec(F)_(1)=-6hat(i)=8hat(j) , N are acting an particle on acting on particle respectively find vec(F)_(3) .