गुणनखंड : 1-2a - 2b - 3(a+b)^(2) | 9 | फ़ैक्टरीकरण | गणित | आईसीएसई | संशय

Solve: a + 2b =4, 2a +b =9 .

1a^(2)+5+b=9a^(2)+15+b

factorize : 9a^2+3a-8b-64b^2

sin ^ (- 1) (a- (a ^ (2)) / (3) + (a ^ (3)) / (9) + (a ^ (3)) / (9) +) + cos ^ ( -1) (1 + b + b ^ (2) +) = (pi) / (2) sin a - + ... + cos11 + b + b2 + ...

The following steps are involved in finding the value of 10 (1)/(3) xx 9(2)/(3) by using an appropriate indentity . Arrange them in sequential order . (A) (10)^(2) - ((1)/(3))^(2) = 100 - (1)/(9) (B) 10(1)/(3) xx 9(2)/(3) = (10 + (1)/(3)) (10 - (1)/(3)) (C) (10 + (1)/(3)) (10 - (1)/(3)) = (10)^(2) - ((1)/(3))^(2) [because (a + b) (a -b) = (a^(2) - b^(2))] (D) 100 - (1)/(9) = 99 + 1 - (1)/(9) = 99(8)/(9)

25a^2-9 is factored as: 25a^2-9 का गुणनखंड होगा :

Find the value of a and b . (sqrt11 - sqrt7 ) / (sqrt 11 + sqrt 7) = a - b sqrt 77 (i) a = 9/2 , b = 1/2 (ii) a = 2/9, b = 2/3 (iii) a = 2/5, b = 1/2 (iv) a = 9/2, b =5/2