गुणा करें: ( a/7+(a^2)/9)by\ (b/2-(b^2)/3) (3x^2y-5x y^2)by\ (1/5x^2+1 /3y^2) | 8 | बीजगणितीय पूर्व...

Multiply: ((a)/(7)+(a^(2))/(9))by((b)/(2)-(b^(2))/(3))(3x^(2)y-5xy^(2))by((1)/(5)x^(2)+(1)/(3)y^(2))

3x+2y=5 2x+3y=7

3x+2y=5 2x-3y=7

(5x + 3y) (5x-3y) (25x ^ (2) + 9y ^ (2))

3 - [x - {2y - (5x + y - 3) + 2x^(2)} - (x^(2) - 3y)]

Subtract: (i) -8xy from 7xy (ii) x^(2) from -3x^(2) (iii) (x - y) from (4y - 5x) (iv) (a^(2) + b^(2) - 2ab) from (a^(2) + b^(2) + 2ab) (v) (x^(2) - y^(2)) from (2x^(2) - 3y^(2) + 6xy) (vi) (x -y + 3z) from (2z - x - 3y)

Factorise 25x^(2) - 30xy + 9y^(2) . The following steps are involved in solving the above problem . Arrange them in sequential order . (A) (5x - 3y)^(2) " " [ because a^(2) - 2b + b^(2) = (a-b)^(2)] (B) (5x)^(2) - 30xy + (3y)^(2) = (5x)^(2) - 2(5x)(3y) + (3y)^(2) (C) (5x - 3y) (5x - 3y)