दो प्रक्रम है A^(+) l_1 থেকে A^(2+) + e^(-) এবং A^(2+) +l_2 toA^(3+) + e^(-) l_1 and l_2 এর জন্য সত। ..

If l_(1),l_(2) and l_(3) are the orders of the currents through our nerves, domestic appliances and average lightening, then the correct order of currents is (1) l_(1) gt l_(2) gt l_(3) (2) l_(1) gt l_(3) gt l_(2) (3) l_(1) lt l_(2) lt l_(3) (4) l_(1) = l_(2) = l_(3)

Show that the matris [[l_(1),m_(1),n_(1)],[l_(2),m_(2),n_(2)],[l_(3),m_(3),n_(3)]] is orthogonal, if l_(1)^(2) + m_(1)^(2) + n_(1)^(2) = Sigmal_(1)^(2) = 1 = Sigma l_(2)^(2) = Sigma_(3) ^(2) and l_(1) l_(2) + m_(1)m_(2) + n_(1) n_(2) = Sigma l_(1)l_(2) =0 = Sigma l_(2)l_(3) = Sigma l_(3) l_(1).

Questions based on L1 and L2

In the following circuit find l_1 and l_2 :-

If a != 1 and l n a^(2) + (l n a^(2))^(2) + (l n a^(2))^(3) + ... = 3 (l n a + (l n a)^(2) + ( ln a)^(3) + (l n a)^(4) + ....) then 'a' is equal to

int(e^(5l nx)-e^(4l nx))/(e^(3l nx)-e^(2l nx))dx

If l_1: (x-5)/3=(y-7)/(-16)=(z-3)/7 and l_2:(x-9)/3=(y-13)/8=(z-15)/(-5) the (A) l_1 and l_2 intersect (B) l_1 and l_2 are skew (C) distance between l_1 and l_2 is 14 (D) none of these

int_ (0)^(4 pi) e^(t) (sin^(6) at+cos^(4) at) dtint_ (0)^(pi) e^(t) (sin^(6) at+ cos^(4) at) dta = 2, L = (e^(4 pi) -1)/(e^(pi) -1) (ii) a = 2, L = (e^(4 pi)+ 1)/(e^(pi) +1) (iii) a = 4, L = (e^(4 pi) -1)/(e^(pi) -1) (iv) a = 4, L = (e^(4 pi) +1)/(e^(pi) +1)

Let L be the set of all straight lines in plane. l_(1) and l_(2) are two lines in the set. R_(1), R_(2) and R_(3) are defined relations. (i) l_(1)R_(1)l_(2) : l_(1) is parallel to l_(2) (ii) l_(1)R_(2)l_(2) : l_(1) is perpendicular to l_(2) (iii) l_(1) R_(3)l_(2) : l_(1) intersects l_(2) Then which of the following is true ?