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A train starting from a railway station and moving with uniform acceleration attains a speed of 40km//h in 5 min. find its acceleration.

A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/hr in 10 minutes.Find its acceleration

(a) Derive the formula : s=ut+(1)/(2)at^(2) , where the symbols have usual meanings. (b) A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.

A body starts from rest and then moves with uniform acceleration. Then.

A train starts from rest and moves with uniform acceleration alpha for some time and acquires a velocity v it then moves with constant velocity for some time and then decelerates at rate beta and finally comes to rest at the next station. If L is distance between two stations then total time of travel is

A motor car, starting from rest, moves with uniform acceleration and attains a velocity of 8 ms^(-1) in 8 s. It then moves with uniform velocity and finally brought to rest in 32 m under unifrom retardation. The total distance covered by the car is 464 m. Find the acceleration.

A train starts from station A with uniform acceleration a_(1) . For some distance and then groes with uniform retardation a_(2) for some more distance to come to rest at station B . The distance between stations A and B is 4 km and the train takes 1//5 h compete this journey. If accelerations are in km per mimute unit, then show that (1)/(a_(1)) +(1)/(a_(2)) =x . Find the value of x .

A train starting from rest moves with a uniform acceleration of 0.2 m//s^(2) for 5 minutes . Calculate the speed acquired and the distance travelled in this time.

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