यदि A = [(cos theta,sin theta),(sin theta,cos theta)], B = [(cos phi,sin phi),(sin phi,cos phi)]...

If A=[[cos theta, sin theta],[sin theta, cos theta]],B=[[cos phi, sin phi],[sin phi, cos phi]] show that AB=BA.

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi), (cos phi sin phi,sin^2 phi)]=0

If A=[(cos^2theta,costheta sintheta),(cos theta sintheta, sin^2theta)] and B=[(cos^2 phi, cos phi sin phi),(cos phisinphi,sin^2phi)], show that AB is zero matrix if theta and phi differ by an odd multiple of pi/2.

Flind the product of two matrices A =[[cos^(2) theta , cos theta sin theta],[cos theta sin theta ,sin^(2)theta]] B= [[cos^(2) phi,cos phi sin phi],[cos phisin phi,sin^(2)phi]] Show that, AB is the zero matrix if theta and phi differ by an odd multipl of pi/2 .

If theta, phi epsilon R , then the determinant Delta=|(cos theta, - sin theta, 1),(sin theta, cos theta, 1),(cos(theta+phi),-sin(theta+phi),0)| lies in the interval

The value of the determinant ,cos(theta+phi),-sin(theta+phi),cos2 phisin theta,cos theta,sin phi-cos theta,sin theta,cos phi]| is