Al(OH)_(3)=10^(-36) का K_(sp) और E_(Al^(3+)//Al)^(@)=-1.66V Al^(3+) की कमी क्षमता //अल...

Al(OH)_(3) is

K_(sp) of Al(OH)_(3)=10^(-36) and E_(Al^(3+)//Al)^(@)=-1.66V Reduction potential of Al^(3+)//Al couple at pH=12 and 298K is

Arrange the following metals in increasing order of their reducing power. [ Given : E_(K^(+)//K)^(@)=-2.93V, E_(Ag^(+)//Ag)^(@)=+0.80V, E_(Al^(3)//Al)^(@)=-1.66V, E_(Au^(3+)//Au)^(@)=+1.40 V, E_(Li^(+)//Li)^(@)=-3.05 V ]

What is the ratio of moles of Mg(OH)_(2) and Al(OH)_(3) , present in 1L saturated solution of Mg(OH)_(2) and Al(OH)_(3) K_(sp) of Mg(OH)_(2)=4xx10^(-12) and K_(sp) of Al(OH)_(3)=1xx10^(-33) .[Report answer by multiplying 10^(-18)]

(i) State Kohlrausch law. (ii) Calculate the emf of the following cell at 298 K: Al(s)//Al^(3+) (0.15M)//Cu^(2+)(0.025M) //Cu(s) (Given E^(@)(Al^(3+)//Al) = -1.66 V, E^(@)(Cu^(2+)//Cu) = 0.34V, log 0.15 = -0.8239, log 0.025 = - 1.6020)

At what minimum pH will 10^(-3) mol of Al(OH)_(3) go into solution (V = 1L) as Al(OH)_(4) and at what maximum pH it will dissolve as Al^(3+) ? Given Al (OH)_(4)^(-) hArr Al^(3+) +4OH^(-) , K_(eq) = 1.3 xx10^(-34) Al(OH)_(3)hArr Al^(3+) +3OH^(-) , K_(sp) = 5.0 xx10^(-33)

Calculate E^(@) for the cell : Al|Al^(3+)(1 M)||Cu^(2+)(1M)|Cu Given : E_(Al^(3+)//Al)^(@) and E_(Cu^(2+)//Cu)^(@) as -1.66 V and + 0.34 V respectively