144 eV এর গতিশক্তির সাথে চলমান ইলেক্ট্রনের ডি ব্রোগলি তরঙ্গদৈর্ঘ্য প্রায় | ক্লাস 12...

An electron in Li^(2+) ion makes a transition from higher state n_(2) to lower state n_(1)=6. The emitted photons is used to ionize an electron in H-atom from 2nd excited state. The electron on leaving the H-atom has a de Broglie wavelength lambda-12.016 "Å" .Find the value of n_(2). Note : Use (12.016)^(2)= (150xx144)/(13.6xx11),lambda_("Å")=sqrt((150)/(KE_(eV)))

Deuterum atoms in the ground state are radiated by photons of energy 12.8 eV What will be the energy of induced radiation of longest wavelength? Lonisation energy of deuterium is 14.4 eV .