একটি সমান্তরাল ABCD তে। প্রমাণ করুন যে vec(AC)+ vec (BD) = 2 vec(BC) | 12 | মৌলিক গণিত & VE...

A parallelogram ABCD. Prove that vec(AC)+ vec (BD) = 2 vec(BC) '

If ABCD is a parallelogram, then vec(AC) - vec(BD) =

Find |vec(A) xx vec(B)| if |vec(A)| = 10|vec(B)| = 2 and vec(A).vec(B) = 12

ABCD is a parallelogram Fig. 2 (c ) .64. AC and (BD) are its diagonals. Show that (a) vec (AC) +vec (BD) =2 vec (BC) (b) vec (AC) - vec (BD) =2 vec (AB) .

For any four points A,B,C,D |vec (AB) xx vec (CD)-vec (BC) xx vec (AD)+vec (CA) xx vec (BD)| is equal to 4 times the area of triangle- (1) ABC (2) BCD (3) ACD (4) ABD

If ABCDE is a pentagon, then vec(AB) + vec(AE) + vec(BC) + vec(DC) + vec(ED) + vec(AC) is equal to

If |vec A|=10 , |vec B|=2 , and vec A . vec B = 12 , |vec A xx vec B| =_____.

ABCD a parallelogram, and A_1 and B_1 are the midpoints of sides BC and CD, respectively. If vec(aA)_1 + vec(AB)_1 = lamda vec(AC) , then lamda is equal to

In the parallelogram ABCD,vec AC^(2)-vec BD^(2)=