ಸಾಲು y - x - 1 +λ= 0 ಸಮಾನವಾಗಿ ಅಕ್ಷಗಳಿಗೆ ಒಲವನ್ನು ಹೊಂದಿದ್ದರೆ ಮತ್ತು ಬಿಂದುಗಳಿಂದ ಸಮನಾಗಿರುತ್ತದೆ (1, - 2) ಮತ್ತು ...

(2x -2y+3) dx -(x-y+1) dy=0 , " when" x=0, y=1

y = e ^ (xx) x tan ^ (- 1) x, showthat (1 + x ^ (2)) y_ (2) -2 (1-x + x ^ (2)) y_ (1) + (1 -x ^ (2)) y = 0

The area bounded by y-1 = |x|, y = 0 and |x| = (1)/(2) will be :

If y = y (x) is the solution curve of the differential equation x^2dy + (y - 1/x) dx = 0, x gt 0 , and y(1) = 1, " then " y (1/2) is equal to

If y = y (x) is the solution curve of the differential equation x^2dy + (y - 1/x) dx = 0, x gt 0 , and y(1) = 1, " then " y (1/2) is equal to

If cos ^ (- 1) x + cos ^ (- 1) y = (pi) / (2), tan ^ (- 1) x-tan ^ (- 1) y = 0 then x ^ (2) + xy + y ^ (2) =

STATEMENT-1 : The centroid of a tetrahedron with vertices (0, 0,0), (4, 0, 0), (0, -8, 0), (0, 0, 12)is (1, -2, 3). and STATEMENT-2 : The centroid of a triangle with vertices (x_(1), y_(1), z_(1)), (x_(2), y_(2), z_(2)) and (x_(3), y_(3), z_(3)) is ((x_(1)+x_(2)+x_(3))/3, (y_(1)+y_(2)+y_(3))/3, (z_(1)+z_(2)+z_(3))/3)

( 1 ) /(x) + (1 ) /( y) = 7 , ( 2)/(x) + ( 3) /( y) = 17 (x ne 0, y ne 0 ) .

If the points (x_1, y_1), (x_2, y_2) and (x_3, y_3) be collinear, show that: (y_2 - y_3)/(x_2 x_3) + (y_3 - y_1)/(x_3 x_2) + (y_1 - y_2)/(x_1 x_2) = 0

A=[[1, 0, 2], [-1, 1, -2], [0, 2, 1]] and adjA=[[5, x, -2], [1, 1, 0], [-2, -2, y]] , then (x, y)=