If the value of universal gravitational constant is `6.67xx10^(11) Nm^2 kg^(-2),`

The value of universal gravitational constant G=6.67xx10^(-11)Nm^(2)kg^(-2) . The value of G in units of g^(-1)cm^(3)s^(-2) is

What is the value of universal gravitational constant?

The value of universal gravitational constant is 6.67xx10^(-8) "dyne" g^(-2) cm^2. What is its value in Mks system?

According to Newton's law of gravitational, everybody in this universe attracts every other body with a force, which is directly proportional to the product of their masses and is inversely proportional to the square of the distance between their centres, i.e., F prop (m_(1)m_(2))/(r^(2)) or F = (Gm_(1)m_(2))/(r^(2)) where G is universal gravitational constant = 6.67 xx 10^(-11) Nm^(2) kg^(-2) . (i) What is the value of G on the surface of moon? (ii) How is the gravitational force between two bodies affected when distance between them is halved? (iii) What values of like do you learn from this law?

Calculate the force of attraction between two balls each of mass 10kg when their centres are 10 cm apart. The value of gravitational constant G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)

The mass of a planet is 6xx10^(24) kg and its diameters is 12.8 xx 10^(3) km. If the value of gravitational constant be 6.7xx10^(-11) NM^(2)//Kg^(2) ,Calculate the value of acceleration due to gravity on the surface of the planet.What planet could this be ?