यदि mu = {-5,-4,-3,-2,-1,0,1,2,3,4,5} A = {(x)/(x^(2)) = 25, x in Z} B= {(x)/(x^(2)) + 5 =9, x में...

If mu = {-5,-4,-3,-2,-1,0,1,2,3,4,5} A = {(x)/(x^(2)) = 25, x in Z} B = {(x)/(x^(2)) + 5 =9, x in Z} and C = {(x)/(-2) le x le 2, x in Z} then (A nn B nn C)^(C ) nn(A Delta B)^(C ) =

If 5x - (1)/(2x) = 3 , then find 25x^(2) + (1)/(4x^(2)) .

Solve for x (1)/( 2x -3) + (1)/(x -5) =1," " x ne 3/2,5

If |{:(x, 2, 3),(2,3,x),(3 , x,2):}| = |{:(1, x, 4),(x,4,1),(4 , 1,x):}| = |{:(0, 5, x),(5,x,0),(x, 0,5):}| = 0, then the value x equals (x in R )

If x≠ − 1 , 2 and 5, then the simplified value of {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} is equal to: यदि x≠ − 1 , 2 और 5 है तो {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} का सरलीकृत मान बराबर हैः