यदि A_1,A_2 दो AM हैं, तो G_1,G_2 दो GM हैं और H_1,H_2 दो HM हैं...

If A_1,A_2 be two A.M.\'s G_1,G_2 be the two G.M.\'s and H_1,H_2 be the two H.M.\'s between a and b then (A) (A_1+A_2)/(G_1 G_2)=(a+b)/(ab) (B) (H_1+H_2)/(H_1 H_2)=(a+b)/ab (C) (G_1G_2)/(H_1 H_2)=(A_1+A_2)/(H_1+H_2) (D) (A_1+A_2)/(H_1 H_2)=(a+b)/(a-b)

If A_1, A_2, G_1, G_2, ; a n dH_1, H_2 are two arithmetic, geometric and harmonic means respectively, between two quantities aa n db ,t h e na b is equal to A_1H_2 b. A_2H_1 c. G_1G_2 d. none of these

If A_1,A_2,G_1,G_2 and H_1,H_2 are AM’s, GM’s and HM’s between two numbers, then (A_1+A_2)/(H_1+H_2). (H_1H_2)/(G_1G_2) equals _____

If A_(1),A_(2),G_(1),G_(2) and H_(1),H_(2) be two AMs,GMs and HMs between two quantities then the value of (G_(1)G_(2))/(H_(1)H_(2)) is

Two AMs. A_1 and A_2 , two GMs. G_1 and G_2 and two HMs. H_1 and H_2 are inserted between any two numbers. Then find the arithmetic mean between H_1 and H_2 in terms of A_1, A_2, G_1, G_2 .

Two numbers are in ratio 6:11, If there HCF is 28, then the sum of these two numbers is: दो संख्याएं 6: 11 के अनुपात में हैं | यदि उनका महत्तम समापवर्तक 28 हैं तो इन दो संख्याओं का योग क्या हैं?

A_1, A_2,...., A_n are n A.M’s, and H_1, H_2,....., H_n are n H.M’s inserted between a and b . Prove that (A_1 +A_n)/(H_1+H_n)lt (A^2)/(G^2) , where A is the arithmetic mean and G is the geometric mean of a and b .

Let a_1,a_2 ,…. , a_10 be in A.P. and h_1,h_2 …. h_10 be in H.P. If a_1=h_1=2 and a_10 = h_10 =3 , then a_4 h_7 is :