वृत्त x^(2) + y^(2) - 8x - 10 y - 8 = 0की उन स्पर्श रेखाओं के समीकरण ज्ञात कीजिए जो रेखा 12y - 5...

3x^(2) + 8x +4=0, 4y^(2)-19y + 12=0

{:(x - 2y = 8),(5x - 10y = 10):}

(i) 15x^(2) - 8x + 1 = 0 (ii) 6y^(2) - 19y + 10 = 0

(x + y) ^ (10) = x ^ (8) y ^ (2)

I. X^(2) - 8x+15 = 0" "II. Y^(2) -12y + 36 = 0

Equation of radical axis of the circles x^(2) + y^(2) - 3x - 4y + 5 = 0 and 2x^(2) + 2y^(2) - 10x - 12y + 12 = 0 is

Two circles x^(2) + y^(2) - 4x + 10y + 20 = 0 and x^(2) + y^(2) + 8x - 6y - 24= 0