सदिश vec(a) = 3 hat(i) + 4 hat(j) + 5 hat(k)तथा vec(b) = hat(i) + hat(j) + hat(k)के बीच का कोण न...

Find the (a) scalar component and (b) vector component of vec(A) = 3 hat(i) + 4 hat(j) + 5 hat(k) on vec(B) = hat(i) + hat(j) + hat(k) .

Find the projection of vec(a) = 2 hat(i) - hat(j) + hat(k) on vec(b) = hat(i) - 2 hat(j) + hat(k) .

If vec(a) = 5 hat(i) - hat(j) - 3 hat(k) and vec(b) = hat(i) + 3 hat(j) - 5 hat(k) , find the angle between vec(a) and vec(b) .

Let vec( a) = 2 hat(i) - 3 hat(j) + 4 hat(k) and vec( b) = 7 hat(i) + hat(j) - 6 hat(k) . If vec( r ) xx vec( a) = vec( r ) xx vec( b) , vec( r ) . ( hat(i) +2 hat(j) + hat(k)) = -3 , then vec ( r ). ( 2 hat(i)- 3hat(j) + hat(k)) is equal to :

If vec(a) = hat(i) + 2 hat(j) + 3 hat(k) and vec(b) = 2 hat(i) + 3 hat(j) + hat(k) , find a unit vector in the direction of ( 2 vec(a) + vec(b)) .

If vec(a) = hat(i) + hat(j) + 2 hat(k) and vec(b) = 3 hat(i) + 2 hat(j) - hat(k) , find the value of (vec(a) + 3 vec(b)) . ( 2 vec(a) - vec(b)) .

Find the unit vectors perpendicular to both vec(a) and vec(b) when (i) vec(a) = 3 hat(i)+hat(j)-2 hat(k) and vec(b)= 2 hat(i) + 3 hat(j) - hat(k) (ii) vec(a) = hat(i) - 2 hat(j) + 3 hat(k) and vec(b)= hat(i) +2hat(j) - hat(k) (iii) vec(a) = hat(i) + 3 hat(j) - 2 hat (k) and vec(b)= -hat(i) + 3 hat(k) (iv) vec(a) = 4 hat(i) + 2 hat(j)-hat(k) and vec(b) = hat(i) + 4 hat(j) - hat(k)

If vec(a)= hat(i) - 2hat(j) + 5hat(k) and vec(b) = 2hat(i) + hat(j) -3hat(k) , then (vec(b) - vec(a)).(3 vec(a) +vec(b)) equal to?

verify that vec(a) xx (vec(b)+ vec(c))=(vec(a) xx vec(b))+(vec(a) xx vec(c)) , "when" (i) vec(a)= hat(i)- hat(j)-3 hat(k), vec(b)= 4 hat(i)-3 hat(j) + hat(k) and vec(c)= 2 hat(i) - hat(j) + 2 hat(k) (ii) vec(a)= 4 hat(i)-hat(j)+hat(k), vec(b)= hat(i)+hat(j)+ hat(k) and vec(c)= hat(i)- hat(j)+hat(k).

Find the area of the parallelogram whose adjacent sides are represented by the vectors (i) vec(a)=hat(i) + 2 hat(j)+ 3 hat(k) and vec(b)=-3 hat(i)- 2 hat(j) + hat(k) (ii) vec(a)=(3 hat(i)+hat(j) + 4 hat(k)) and vec(b)= ( hat(i)- hat(j) + hat(k)) (iii) vec(a) = 2 hat(i)+ hat(j) +3 hat(k) and vec(b)= hat(i)-hat(j) (iv) vec(b)= 2 hat(i) and vec(b) = 3 hat(j).