(i) ਫੰਕਸ਼ਨ y = sin x, 0 le x le (pi)/(2) ਦੇ ਗ੍ਰਾਫ਼ ਦਾ ਇੱਕ ਮੋਟਾ ਸਕੈਚ ਬਣਾਓ ਅਤੇ ਨਿਰਧਾਰਤ ਕਰੋ...

If 0 le x le pi/2 then

The function f(x)=cos x, 0 le x le pi is

If cos x=sqrt(1-sin 2x),0 le x le pi then a value of x is

Make a rough sketch of the graph of the function y =2 sin x, 0 le x le (pi)/(2) and determine the area enclosed between the curve, the x-axis and the line x = (pi)/(2).

Find the area bounded by y = sin x, 0 le x le (pi)/(4), y= cos x, (pi)/(4) le x le (pi)/(2) and the x-axis

If pi le x le (3pi)/(2) then sin pi le sinx le sin(3pi)/(2)