यदि सीधी रेखाएं x=-1+s ,y=3-lambdas ,z=1+lambdasa n dx=t/2,y=1+t ,z=2-t ,\nपैरामीटर के साथ...

If the straight lines x=-1+s,y=3-lambda s,z=1+lambda s and x=(t)/(2),y=1+t,z=2-t with paramerters s and t, respectivley,are coplanar,then find lambda

If the straight lines x=1+s,y=-3-lambda s,z=1+lambdas and x=(1)/(2),y=1+t,z=2-t ,with parameters s and t respectively,are co-planar then lambda .Equals

If the straighat lines x=1+s,y=-3-lamdas,z=1+lamdas and x=t/2,y=1+t,z=2-t with parameters s and t respectively, are coplanar, then lamda equals (A) -1/2 (B) -1 (C) -2 (D) 0

If the lines x = 1 + s, y = - 3 - lamda s , z = 1 + lamda s and x = ( t ) / ( s ) , y = 1 + t , z = 2 - t are coplanar, then lamda is equal to

If t is a parameter and x = t + 1/t , y = t - 1/t , " then " (d^2 y)/(dx^2) =

The distance between (5, 1, 3) and the line x = 3, y = 7 + t, z = 1 + t is

If " "x=t^(2),y=t^(3) ," then "(dy)/(dx)" at "t=-1" is "