यदि समीकरण ax^(2)+bx+c=0 के मूल वास्तविक हों एवं (alpha)/(alpha-1) व (alpha+1)/(alpha) रूप के हो...

If roots of the equation ax^(2)+bx+c=0 are (alpha)/(alpha-1) and (alpha+1)/(alpha) and then (a+b+c)^(2) equals

If a and b are roots of the equation ax^2+bx+c=0 , then which equation will have roots (ab+a+b) and (ab-a-b) ? यदि a तथा b समीकरण ax^2+bx+c=0 के मूल हैं, तो किस समीकरण के मूल (ab+a+b) तथा (ab-a-b) होंगे है?

if alpha and beta are the roots of the equation ax^(2)+bx+c=0 and if px^(2)+qx+r=0 has roots (1-alpha)/(alpha) and (1-beta)/(beta) then r=?

If alpha and beta are roots of ax^(2) + bx + c = 0 , then find the value of a((alpha^(2) + beta^(2))/(beta alpha)) + b((alpha)/(beta) + (beta)/(alpha))

If alpha,beta are non-real roots of ax^(2)+bx+c=0,(a,b,c in R), then (A)alpha beta=1(B)alpha=beta(C)(a beta)/(alpha beta)=1(D)alpha=bar(beta)

If alpha,beta are the roots of ax^(2)+bx+c=0 then the value ((alpha)/(beta)-(beta)/(alpha))^(2) is ...

ax^(2)+bx+c=0(a>0), has two roots alpha and beta such alpha 2, then