Thermodynamics Numericals || Part 06 || Heat Capacity || Class 11th || Chap 06 || Vikram hap che

Density of a liquid 'A' is 0.5 g//c.c and that of liquid 'B' is 0.6 g//c.c . Heat capacity of 8 litres of 'A' is equal to that of 10 litres of 'B'. Then the specific heats ratio of A and B is

Calcuate the heat required to convert 0.6 kg of ice at - 20^(@)C , kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given the specific heat capacity of ice =2100 j kg^(-1) K^(-1) , specific heat capacity of water =4186 j kg^(-1) K^(-1) latent heat ice =3.35xx10^(5) j kg^(-1) and latent heat of steam =2.256xx10^(6)j kg^(-1)

Rakhi is a student of class 11th, she is strolling in a park near to her house. She saw a fat girl being teased by two thin playmates. They are playing see-saw. Rakhi enquired why they are teasing their playmate and why they are not allowing her to sit on see-saw. Two thin girls replied that it is not possible to play see-saw with the fat girl as she is very heavy for any of them. Rakhi told them if the fat girl sits slightly near towards the middle part then, they can see-saw even with her. And finally that fat girl is see-sawing with one of thin girl. They finally learn to play that game together (i) What technique is told by Rakhi to little girls? (ii) If mass of fat girl is 30 kg and thin girls are of 20 kg (each), then to operate see-saw properly what will be the ratio of their distances from the pivot of plank? (iii) What values are indicated by Rakhi? (iv) What values are indicated by little girls?

Class 11 NEET 2020 - Revision In 60 Days | Thermodynamics Part 1 - Quick Revision | NEET Physics | Important Questions

Molar Heat Capacity OF Polytropic Process || Conversion OF Polytropic Process || into other Process || Case II :-Solid/Liquid || Case III :-Real Gas || Solved Numerical Class illustration

A study was conduced to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follow: {:("0.03 0.08 0.08 0.09 0.04 0.17"),("0.16 0.05 0.02 0.06 0.18 0.20"),("0.11 0.08 0.12 0.13 0.22 0.07"),("0.08 0.01 0.10 0.06 0.09 0.18"),("0.11 0.07 0.05 0.07 0.01 0.04"):} You were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12-0.16 on any of these days.

A fuel cell is a cell that is continously supplied with an oxidant and a reductant so that if can deliver a current indefinitely. Fuel cells offer the possibility of achieving high thermodynamic efficiency in the conversion of Gibbs energy into mechanical work.Internal combustion engines at best convert only the fraction (T_2-T_1)//T_2 of the heat of combustion into mechanical work. While the thermodynamic efficiency of the fuel cell is given by, eta=(DeltaG)/(DeltaH) , where DeltaG is the Gibbs energy change for the cell reaction and DeltaH is the enthalpy change of the cell reaction.A hydrogen-oxygen fuel cell may have an acidic or alkaline electrolyte. Pt|H_2(g)|H^(+)(aq.)||H_2O(l)|O_(2)(g)|Pt , (2.303 RT)/F=0.06 The above fuel cell is used to produce constant current supply under constant temperature & 30 atm constant total pressure conditions in a cylinder.If 10 moles H_2 and 5 moles of O_2 were taken initially. Rate of consumption of O_2 is 10 milli moles per minute. The half-cell reactions are 1/2O_2(g)+2H^+(aq)+2e^(-)toH_2O(l) E^(@)=1.246 V 2H^+(aq)+2e^(-) to H_2(g) E^(@)=0 To maximize the power per unit mass of an electrochemical cell, the electronic and electrolytic resistances of the cell must be minimized.Since fused salts have lower electolytic resistances than aqueous solutions, high-temperature electrochemical cells are of special interest for practical applications. Calculate e.m.f of the given cell at t=0.(log 2=0.3)