`3.2 g` sulphur combines with `3.2 g` of oxygen, to from a compound in one set of conditions.

6 g of carbon combines with 32 g of sulphur to form CS_(2) . 12 g of C also combine with 32 g of oxygen to form carbon dioxide. 10 g of sulphur combines with 10 g of oxygen to form sulphur dioxide. Which law is illustrated by them?

2 g hydrogen combine with 16 g of oxygen to from water and with 6 g of carbon to form methane. In carbon dioxide 12 h of carbon are combined with 32 g of oxygen. These figures illustrate the law of

In compound A, 1.00 g nitrogen units with 0.57 g oxygen. In compound B, 2.00 g nitrogen combines with 2.24 g oxygen. In compound C, 3.00 g nitrogen combines with 5.11 g oxygen. These results obey the following law

32 g of sulphur will react with 32 g of oxygen, even if more than 32 g of sulphur is available. Which law of chemical combination does it illustrate ?

1 g of oxygen combines with 0.1260 g of hydrogen to form H_(2)O . 1 g of nitrogen combines with 0.2160 g of hydrogen to form NH_(3) . Predict the weight of oxygen required to combine with 1 g of nitrogen to form an oxide.