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Find the minimum energy required to sepa...

Find the minimum energy required to separated a neutron form `._18Ar^(40)`.

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What is the minimum photon energy required to remove the least bound neutron of ._(20)^(40)Ca and ._(18)^(40)Ar . The nesessary atomic masses (in mu ) are given below: {:(M(.^(40)Ca)=39.962591 u),(M(.^(39)Ca)=38.970719 u),(M(.^(40)Ar)=39.962383 ),(M(.^(39)Ar)=38.964314 u),(" "m_n=1.008665 u):}

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The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separartion energy of the nuclei ._(20)Ca^(41) and ._(13)Al^(27) form the following data : m(._20Ca^(40))=39.962591u and m(._(20)Ca^(41))=40.962278u m(._(13)Al^(26))=25.986895u and m(._(13)Al^(27))=26.981541u

A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separated all the neutrons and protons form each other. for simplicity, assume that the coin is entirely made of ._29Cu^(63) atoms (of mass 62.92960 u).

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