a तथाb का मान ज्ञात कीजिये जिसके लिए निकाय [(3,-2,1),(5,-8,9),(2,1,a)][(x),(y),(z)]=[(b),(3),(-1...

- यदि nc8 = nc2, तो n का मान ज्ञात कीजिये ?

If [(2,-1,3),(1,3,-1),(3,2,1)],[(x),(y),(z)]=[(9),(4),(10)] ,then [(x),(y),(z)] is equal to

(x+1)/(2)+(y-1)/(3)=8;(x-1)/(3)+(y+1)/(2)=9

Consider the system of equations [[3,-2,1],[5,-8,9],[2,1,a]][[x],[y],[z]]=[[b],[3],[-1]] The values of a,b for which the above system has no solution a=-3,b in R a=-3,b=(1)/(3) a!=-3,b!=(1)/(3) a=-3,b!=(1)/(3)

Find an equation, whose roots are (1)/(2) and (1)/(3) / ऐसा समीकरण ज्ञात कीजिए जिसके मूल (1)/(2) तथा (1)/(3) हैं -

Determination the product [{:(,1,-1,1),(,1,-2,-2),(,2,1,3):}] [{:(,-4,4,4),(,-7,1,3),(,5,-3,-1):}] and use it to solve the system of equations x-y+z=4, x-2y-2z=9, 2x+y+3z=1

Find is the value / मान ज्ञात करें: 3/4 of (1/3 div 1/2)+(2-2/5)xx3/2+2/3

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3)and(x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .