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एक सरल रेखा के अनुदिशगतिशील कण कि समयाश्रित (time dependent) स्थिति s समीकरण s = 5t - 10 t^(2) स...

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If displacements of a particle varies with time t as s = 1/t^(2) , then.

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The displacement x of a particle is dependent on time t according to the relation : x = 3 - 5t + 2t^(2) . If t is measured in seconds and s in metres, find its acceleration at t = 4s.

A particle is thrown with a velocity of u m/s. It passes A and B as shown in figure at time t_(1) = 1 s and t_(2) = 3 s. The value of u is (g = 10 m//s^(2))

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(a) The displacement s of a particale in time t related as s = alpha + beta t + gamma t^(2) + delta t^(2) (b) The veloctiy v of particle varies with time as v = alpha t + beta t^(2) + (gamma )/(t + s) Findk the dimension fo alpha, beta, gamma and delta .

The acceleration a of alpha of a particle depends on displacements covered in a time t as a= S + 5 . It is given that initially S=0 m and v=5m//s . Then

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