0.01 M CH_(2)COOH समाधान के लिए, wedge_(m)=7.8 ओमेगा^(-1)cm^(2) mol^(-1) यदि wedge_(m)^(@)=390Om...

For a 0.01 M CH_(2)COOH solution, wedge_(m)=7.8 Omega^(-1)cm^(2) mol^(-1) if wedge_(m)^(@)=390Omega^(-1)cm^(2)mol^(-1) . What is the degree of the dissociation (alpha) of acetic acid ?

From the following molar conductivities at infinite dilution : wedge_(m)^(@) for Ba(OH)_(2)=457.6Omega^(1)cm^(2)mol^(-1) wedge_(m)^(@) for BaCl_(2)=240.6Omega^(-1) cm^(2)mol^(-1) wedge_(m)^(@) for NH_(4)Cl=129.8 Omega^(-1) cm^(2) mol^(-1) Calculate wedge_(m)^(@) for NH_(4)OH .

What is the value of pK_(b)(CH_(3)COO^(c-)) if wedge^(@)._(m)=390 S cm^(-1) mol ^(-1) and wedge_(m)=7.8 S cm^(2) mol^(-1) for 0.04 M of CH_(3)COOH at 25^(@)C ?

Molar conductivity of aqueous solution of HA is 200 S cm^(2) "mol"^(-1) , pH of this solution is 4. Calculate the value of pK_(a) (HA) at 25^(@) C Given: wedge_(M)^(infty) (NaA) = 100 S cm^(2) mol^(-1), wedge_(M)^(infty)(HCl)= 425 Scm^(2) "mol"^(-1) , wedge_(M)^(infty)(NaCl) = 125 Scm^(2)"mol"^(-1) .

Which of the following statemetn is // are correct ? I . Van't Hoff factor for 10^(-3) M CH_(3)COOH is 39//35 (wedge^(@)._(m)=350 S cm^(2) mol^(-1) and k=4xx10^(-5) S cm^(-1)). II. If wedge^(@)._(m) of KCl, LiCl, and KNO_(3) are 150, 115, and 145 S cm^(2) mol^(-1), then that of LiNO_(3) will be 110 S cm^(2) mo^(-1). III. In general, with increase in concentration, the specific conductance increases and reaches a maximum and then decreases with further increase in concentration.