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The EMF of the cell Ni |Ni|Ni^(2+) ||Cu^...

The EMF of the cell Ni `|Ni|Ni^(2+) ||Cu^(2+) |Cu(s)` is `0.59 ` volt. The standard reduction

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The standard EMF of the cell : Ni| Ni^(2+)||Cu^(2+)|Cu is 0.59 volt The standsard elctrode potential (reduction potential of copper electrode is 0.34 volt . Calculate the standsard electrode potential of nickel electrode

Calculate the standard electrode potential of Ni^(2+) /Ni electrode if emf of the cell Ni_((s)) |Ni^(2+) (0.01M)| |Cu^(2)| Cu _((s))(0.1M) is 0.059 V. [Given : E_(Cu^(2+)//Cu)^(@) =+0.34V]

The cell potential for the cell Ni|Ni^(2+)(1M)||Cu^(2+)(1M)|Cu is 0.59 V and E(Cu^(2+)|Cu) = +0.34 V . What is the standard electrode potential of Ni^(2+)|Ni electrode?

The cell reaction of a cell is Mg(s)+Cu^(2+)(aq)rarrCu(s)+Mg^(2+)(aq) if the standard reduction potential of Mg and Cu are -2.37 V and +0.34 V respectively The emf of the cell is