4 PM - CLASS 12 JEE PHYSICS TUTORIAL | DC CIRCUIT T-8 | SHAHBAZ SALIM | VMC

12:30 PM JEE Mains 2020 - Physics | Current Electricity - 30 Days Score Booster Course

Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows: 1 6 2 3 5 12 5 8 4 8 10 3 4 12 2 8 15 1 17 6 3 2 8 5 9 6 8 7 14 12 (i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals as 5 - 10. (ii) How many children watched television for 15 or more hours a week?

Consider the following R-L-C circuit in which R= 12 Omega . X_(L)= 24 Omega , X_(C)= 8 Omega . The emf of source is given by V = 10 sin (100pit)V . Find the energy dissipated in 10 min. If resistance is removed from the circuit and value of inductance is doubled, express variation of current with time t in the new circuit.

the daily minimum temperatures in degrees Celsius recorded in a certain Arctic region are as follows: -12. 5 ,-10. 8 ,-18. 6 ,-8. 4 ,-10. 8 ,-4. 2 ,-4. 8 ,-6. 7 ,-13. 2 , -11. 8 ,-2. 3 , 1.2 , 2.6 ,0,-2. 4 ,0, 3.2 , 2.7 , 3.4 ,0,-2. 4 ,-2. 4 ,0, 3. 2 , 2.7 , 3.4 ,0,-2. 4 ,-5. 8 ,-8. 9 ,-14 ,6,-12. 3 ,-11. 5 ,-7. 8 ,-2. 9 Represent them as frequency distribution table taking -19. 9\ to-15 as the first class interval.

A current of 4 A flows in a coil when connected to a 12 V dc source. If the same coil is connected to a 12 V, 50 rad s^(-1) ac source, a current of 2.4 A flows of the coil in the circuit. The power developed in the circuit of a 2500 (mu)F capacitor that is connected in series with the coil is

A current of 4 A flows in a coil when connected to a 12 V dc source. If the same coil is connected to a 12 V, 50 rad s^(-1) ac source, a current of 2.4 A flows of the coil in the circuit. The inductance of the coil is

The marks obtained (out of 20) by 30 students of a class in a test are as follows: 14, 16, 15, 11, 15, 14, 13, 16, 8, 10, 7, 11, 18, 15, 14, 19, 20, 7, 10, 13, 12, 14, 15, 13, 16, 17, 14, 11, 10, 20. Prepare a frequency distribution table for the above data using class intervals of equal width in which one class interval is 4-8 (excluding 8 and including 4).

In the circuit shown in figure, E = 10 V, r = 1Omega , R = 4Omega and L = 5H. The circuit is closed at time t = 0. Then, match the following two columns. {:(,"Column I",,"Column II"),(A.,V_(AD)" at t = 0",p,4 V),(B.,V_(BC)" at t = 0",q,8 V),(C.,V_(AB)" at t ="oo,r.,0V),(D.,V_(AD)" at t"=oo,s.,10V):}