"सरल बनाएं: `(m^2-n^2m)^2+2m^3n^2`"

(m^(2)-n^(2))^(2)+2m^(2)n^(2)

Simplify. (i) (a^2-b^2)^2 (ii) (2x+5)^2-(2x-5)^2 (iii) (7m-8n)^2+(7m+8n)^2 (iii) (4m+5n)^2+(5m+4n)^2 (iv) (2.5p-1.5q)^2-(1.5p-2.5q)^2 (v) (ab+ba)^2-2ab^2c (vi) (m^2-n^2m)^2+2m^3n^2

The value of (m+n)^2+(m-n)^2 is

Find the squre root of (m^(n^(2)) n^(m^(2)) a^((m +n)))/((m + n)^((m +n)^(2)))

if m+n=5 and mn= 6, but (m^2 + n^2) (m^3 + n^3) = how much?

The distance between the points (m,-n) and (-m,n) is (A) sqrt(m^2 + n^2) (B) m+n (C) 2 sqrt(m^2+n^2) (D) sqrt(2m^2 +2n^2)

If tan theta+sin theta=m and tan theta-sin theta=n then m^(2)-n^(2)=4mn(b)m^(2)+n^(2)=4mnm^(2)-n^(2)=m^(2)+n^(2)(d)m^(2)-n^(2)=4sqrt(mn)