A train starts from rest and moves with a constant accelerationof 2.0`m/s^2

A train starte from rest and moves with a constant acceleration of 2ms^(-2) for half a minute. The brakes are then applied and the train comes to rest in one minute.find (i) the maximum speed attained by the train (ii) the total distance moves by the train and (ii) the positions (s) of the train a half the maximum speed.

A particle starts from rest and moves with a constant acceleration of 4 m//s^(2) for 10 s , then it moves under constant seceleration and stops in 20 s . Find (a) the maximum velocity attained by the particle (b) the total distance traveled and (c ) the distance/distances from the origin, when the particle is moving at half the maximum velocity.

A cyclist starts from rest and moves with a constant acceleration of 1 m//s^(2) . A boy who is 48 m behind the cyclist starts moving with a constant velocity of 10 m//s . After how much time the boy meets the cyclist?

A bus starts from rest and moves with constant acceleration 8 m//s^(2) . At the same time, a car traveling with a constant velocity 16 m//s overtakes and passes the bus. After how much time and at what distance the bus overtakes the car?

(a) A body starting from rest moves with a constant acceleration of 5 m//s^(2) . What is velocity of the body after 10 sec ? (b) A scooter moving with a velocity of 18 km//h is brought to rest in 5 s by applying brakes. What is the acceleration produced ?

A train starting from rest moves with a uniform acceleration of 0.2 m//s^(2) for 5 minutes . Calculate the speed acquired and the distance travelled in this time.

A boy is moving with constant velocity 12 m//s . When he is 32 m behind a cyclist, the cyclist starts from rest and moves under constant acceleration 2 m//s^(2) . After how much time the boy meets the cyclist? Explain reason for two answers.

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is