हल करें - (2x-1)^(2)=(x-1)(x-3)+1 | 10 | द्विघात समीकरण | MATHS | DAS GUPTA | Doubtnut

(x-3)/(9)-(x-2)/(10)=1

7x-1 / 4-1 / 3 (2x-1-x / 2) = 10/3

Solve: 1/(x+1)+1/(x+2)=2/(x+10)

If (x+4)^3+(2x+1)^3+(2x+5)^3= (3x +12) (2x +1)(2x +5) , then what is the value of x ? यदि (x+4)^3+(2x+1)^3+(2x+5)^3= (3x +12) (2x +1)(2x +5) है, तो x का मान ज्ञात करें |

((4x-3) / (2x + 1))-10 ((2x + 1) / (4x-3)) = 3, x! =-1/2, 3/4

If f(x)={x^(2)+1,0<=x<1,-3x+5,1<=x<=2

If (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) and x ne 1/3 then x=? यदि (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) है तथा x ne 1/3 है, तो x=?

(i) (x ^ (3) + 2x ^ (2) + 3x) -: 2x (ii) (10x-25) - :( 2x-5) (iii) (x (x + 1) (x + 2 ) (x + 3)) - :( x (x + 1))

((x+1)/(x^(2/3)-x^(1/3)+1)-(x-1)/(x-x^(1/2)))=