A charged capacitor C_1 is discharged through a resistance R by putting switch S in position 1 o...

A charged capacitor is discharged through a resistance. The time constant of the circuit is eta . Then the value of time constant for the power dissipated through the resistance will be

When a charged capacitor is discharged through a resistor, heat is produced in the resistor In charging a capacitor, energy is stored in the capacitor.

In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch (S_1) . Also when (S_1) is opend and (S_2) is closed the capacitor is connected in series with inductor (L). At the start, the capicitor was uncharged. when switch (S_1) is closed and (S_2) is kept open, the time constant of this circuit is tau . which of the following is correct

A charged capacitor discharges through a resistance R with time constant tau . The two are now placed in series across an AC source of angular frequency omega =1/(tau) . The impedance of the circuit will be

In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch (S_1) . Also when (S_1) is opend and (S_2) is closed the capacitor is connected in series with inductor (L). When the capacitor gets charged compleely, (= (S_1) is opened and (S_2) is closed, Then,

The figure-3.375 shows two circuits with a charged capacitor that is to be discharged through a resistor as shown in the figure. The ratio of initial charges on capacitors is given as q_(2)//q_(1) = 2 . If both switches are closed at time t= 0 , the charges become equal at 10^(-4) ln 2 s . Find the resistance R.

In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch (S_1) . Also when (S_1) is opend and (S_2) is closed the capacitor is connected in series with inductor (L). Given taht the total charge stored in the LC circuit is (Q_0) . for Tge0, the charge on the capacitor is

A charged capacitor is allowed to discharged three a resistor 2 Omega by closing the switch S at the t=0 . At time t = 2 mus , the reading of the falls half of its initial value. The resistance of ammeter is equal to

A capacitor charged to 10 V is being discharged through a resistance R. At the end of 1 s, the voltage across the capacitor is 5 V . What will be the voltage after 2 s?