The energy released by fission of one `U^(235)` atom is 200 MeV. Calculate

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :

Calculate the amount of ""_(92)U^(235) required to release energy of 1 kWh. Given energy released during fission of one atom is 200 MeV.

The enegry released per fission of .^(235)u is nearly

What is the energy released by fassion of 1 g of U^(235) ? (Assume 200 Me V energy is liberated on fission of 1 nucleus)

An explosion of atomic bomb releases an energy of 7.6xx10^(13)J . If 200 MeV energy is released on fission of one .^(235)U atom calculate (i) the number of uranium atoms undergoing fission. (ii) the mass of uranium used in the atom bomb

The energy released per fission of uranium 235 is about 200 MeV. A reactor using U-235 as fuel is producing 1000 kilowatt power. The number of U-235 nuclei undergoing fission per sec is, approximately-

The energy released during the fission of 1kg of U^(235) is a E_1 and that product during the fusion of 1 kg of hydrogen is E_2 . If energy released per fission of Uranium - 235 is 200 MeV and that per fusion of hydrogen is 24.7 MeV , then the ratio E_2/E_1 is

A nuclear reactor using .^(235)U generates 250 MW of electric power. The efficiency of the reactor (i.e., efficiency of conversion of thermal energy into electrical energy) is 25% . What is the amount of .^(235)U used in the reactor per year? The thermal energy released per fission of .^(235)U is 200 MeV .

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)