একটি পরীক্ষায় কাচের প্রতিসরণ সূচকটি `1.45, 1.56, 1.54, 1.44,

In an experiment refractive index of glass was observed to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. The mean absolute error in the experiement is

In an experiment the refractive index of glass was observed to be 1.45 , 1.56 , 1.54 , 1.44 , 1.54 , and 1.53 . Calculate (a). Mean value of refractive index (b). Mean absolute error ( c ) Fractional error (d) Percentage error (e) Express the result in terms of absolute error and percentage error

1.54 20 129 ? 10505

In an experiment, the values of refractive indices of glass were found to be 1.54, 1.53, 1.44, 1.54, 1.56 and 1.45 in successive measurements (i) mean value of refreactive index of glass (ii) mean absolute error (iii) relative error and (iv) percentage error are respectively.

The class marks of a continuous distribution are 1.04, 1.14, 1.24, 1.34, 1.44, 1.54 and 1.54 Is it correct to say the last interval will be 1.55-1.73 ? Justify your answer.

Write 1.56 as a per cent.

1.bar(54)=

Select the suitable alternatives to complete the series. 1/81 , 1/54, 1/36, 1/24 ,……….

If x = (1)/(1.2) + (1)/(3.4) + (1)/(5.6) …….oo, and y = 1 - (1)/(2.3) - (1)/(4.5) - (1)/(6.7)…….oo , then