একটি কণার SHM দেওয়া হয় `y=3 sin omegat + 4 cosomega t` সমীকরণ দ্বারা

The S.H.M. of a particle is given by the equation y=3 sin omegat + 4 cosomega t . The amplitude is

Two equations of two SHM y = a sin (omegat-alpha) and y = a cos (omegat-alpha) . The phase difference between the two is

Two equations of two S.H.M. are y=alpha sin (omegat-alpha) and y=b cos ( omega t -alpha) . The phase difference between the two is

What is the minimum phase difference between two S.H.M.s given by x_(2)= "sin" omega t + "cos" omegat t " and " x_(1)=(1)/(2) "sin" omega t + (sqrt(3))/(2) "cos" omega t

The electric current in a circuit is given by I = 3 sin omegat + 4 cos omegat. The rms current is

The displacement of an eleastic wave is given by the function y=3 sin omega t +4 cos omegat . where y is in cm and t is in second. Calculate the resultant amplitude.

If current 1_(1) = 3A sin omegat and 1_(2)= 4A cos omegat, then 1_(3) is

Four waves are expressed as 1. y_1=a_1 sin omega t 2. y_2=a_2 sin2 omega t 3. y_3=a_3 cos omega t 4. y_4=a_4 sin (omega t+phi) The interference is possible between