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A hypothetical reaction A(2) + B(2) rarr...

A hypothetical reaction `A_(2) + B_(2) rarr 2AB` follows the mechanism as given below: `A_(2) hArr

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A hypothetical reaction : A_(2)+B_(2)rarr 2AB Follows mechanism as given below : A_(2) overset(k_(c))hArr A+A................( fast )" "(k_(C)- is equilibrium constant ) A+B_(2)overset(k_(1))rarrAB+B...............(" slow")" "(k_(1)- rate constant ) A+B underset(K_(2))overset(k_(2))hArrAB...............( fast )" "(k_(2),k_(3)- are rate constant ) Give the rate law.

In hypothetical reaction, A_(2)+B_(2)rarr2AB , follows the follows the mechnism as given below : {:(A_(2)hArrA+A,("fast reaction")),(A+B_(2)rarrAB+B,("slow reaction")),(A+BrarrAB,("fast reaction")):} Give the rate law and order of reaction

Mechanism of a hypothetical reaction X_(2) + Y_(2) rarr 2XY is given below: (i) X_(2) rarr X + X (fast) (ii) X+Y_(2) hArr XY+Y (slow) (iii) X + Y rarr XY (fast) The overall order of the reaction will be :

A reaction A_(2)+B_(2)rarr 2AB occurs by the following mechanism: Ararr A+A … (slow) A+B_(2)rarr AB+B … (fast) A+Brarr AB … (fast) Its order would be

For the hypothetical reaction A_(2)(g) + B_(2)(g) hArr 2AB(g) If Delta_(r)G^(@) and Delta_(r)S^(@) are 20 JK^(-1)mol^(-1) respectively at 200 K. Delta_(r)C_(p) is 20 JK^(-1) mol^(-1) then Delta_(r)H^(@) "at" 400 K is :

The energies of activation for forward and reverse reaction for A_(2)+B_(2) hArr 2AB are 180 kJ "mol"^(-1) and 200 kJ "mol"^(-1) respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ "mol"^(-1) . The enthalpy change of the reaction (A_(2) + B_(2) rarr 2 AB) in the presence of catalyst will be (in kJ "mol"^(-1) ):