The velocity of the particle moving at a speed is 5 m/sec and the normal (radial) acceleration is 10 m/sec^2. vr...

The initial velocity of the particle is 10m//sec and its retardation is 2m//sec^(2) . The distance moved by the particle in 5th second of its motion is

The equation of motion of particle is S=at^(2) +bt+c .If the displcement after 1 sec is 20 m, velo0city after 2 sec is 30 m/ sec and the acceleration is 10m//se^(2) , then

The velocity of a particle at t=0 "is"vecU = 4hati+3hatj"m"//"sec" and a constant acceleration is veca=6hati+4hatj"m"//"sec"^(2) . Find the velocity and displacement of the particle at t=2 sec.

Velocity of particle moving along x-axis is given as v = ( x^(3) - x^(2) + 2) m // sec. Find the acceleration of particle at x=2 meter.

The velocity of a particle at an instant is 10m/s. After 5sec, the velocity of the particle is 20m/s. Find the velocity at 3 seconds before from the instant when velocity of a particle is 10m/s.

The speed of a particle moving in a circle slows down at a rate of 3 m//sec^(2) . At some instant the magnitude of the total acceleration is 5 m/sec^(2) and the particle's speed is 12 m/sec. The radius of circle will be :

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

Tangental acceleration of a particle moving in a circle of radius 1 m varies with time t as shown in figure (initial velocity of the particle is zero). Time after which total acceleration of particle makes an angle of 30^(@) with radial acceleration is

A particle is moving in x- y plane as shown.The rate of change of speed at point P is 2m/sec find the acceleration a_(y) along y -axis v_(y)=4m/sec ,