निम्नलिखित रेखाओं के बीच की न्यूनतम दूरी ज्ञात कीजिएः (x-3)/1=(y-5)/(-2)=(z-7)/1 और (x+1)/7=(y+1...

Find the shortest distance between the following lines: (x-3)/(1)=(y-5)/(-2)=(z-7)/(1) and (x+1)/(7)=(y+1)/(-6)=(z+1)/(1)

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Reflection of the line (x-1)/(-1)=(y-2)/(3)=(z-3)/(1) in the plane x+y+z=7 is

Find the shortest distance between the lines ( x + 1 ) / ( 7 ) = ( y + 1 ) / ( - 6 )=(z+1)/1 and ( x - 3 ) / ( 1 ) = ( y - 5 ) / ( - 2 ) = ( z- 7 ) / ( 1 ) .

If a line with direction ratios 2:2:1 intersects the line (x-7)/(3)=(y-5)/(2)=(z-3)/(1) and (x-1)/(2)=(y+1)/(4)=(z+1)/(3) at A and B then AB =

If a line with direction ratios 2:2:1 intersects the line (x-7)/(3)=(y-5)/(2)=(z-3)/(1) and (x-1)/(2)=(y+1)/(4)=(z+1)/(3) at A and B then AB=