बगल में दिये परिपथ आरेख में, 10 Omega, 40 Omega, 30 Omega, 20 Omega और 60 Omega के पाँच प्रतिरोध...

In the circuit diagram given below five resistances of 10 Omega, 40 Omega, 30 Omega, 20 Omega and 60 Omega are connected as shown to a 12 V battery. Calculate: (a) total resistance in the circuit (b) total current flowing in the circuit.

In R_1 = 10 Omega, R_2 = 40 Omega and R_3 = 30 Omega, R_4 = 20 Omega, R_5 = 60 Omega and a 12 V battery is connected to the arrangement, calculate. (a) the total resistance and (b) the total current flowing in the circuit. .

In the figure shown, what is the current (in Ampere) drawn from the battery? You are given: R _ 1 = 15 Omega, R _ 2 = 10 Omega, R _ 3 = 20 Omega, R _4 = 5 Omega, R _ 5 = 25 Omega , R _ 6 = 30 Omega, E = 15 V

The resistance of the four arms A, B, C and D of a wheatstone bridge as shown in the figure are 10 Omega , 20 Omega , 30 Omega and 60 Omega respectively . The emf and internal resistance of the cell are 15 V and 2.5 Omega respectively . If the galvanometer resistance is 80 Omega then the net current drawn from the cell will be

Judge the equivalent resistance when the following are connected in parallel. (a) 1 Omega and 10^6 Omega (b) 1 Omega and 10^8 Omega and 10^6 Omega .

Four resistance A = 20 Omega , B = 30 Omega , C = 40 Omega, D = 60 Omega are connected arrange the heats produced per second in them in decreasing order

In the R_(1) = 10 Omega ,R_(2) = 20 Omega, R_(3) = 40 Omega R_(4) = 80 Omega and V_(A) = 5V,V_(B) = 10V,V_(c) = 20V,V_(D) = 15V The current in the resistance R_(1) will be