PCL_(5) 250^(@)C এ মিশ্রণের বাষ্প ঘনত্ব কত হবে যখন এটি বিচ্ছিন্ন হয়ে যায়...

What is the vapour density of mixture of PCL_(5) at 250^(@)C when it has dissociated to the extent of 80% ?

For reaction, PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) the value of K_(c) at 250^(@)C is 26. The value of K_(p) at this temperature will be .

PCl_(5) s dissociating 50% at 250^(@)C at a total pressure of P atm. If equilibrium constant is K_(p) , then which of the following relation is numerically correct -

Under what pressure must an equimolar mixture of PCl_(5) and Cl_(2) be placed at 250^(@)C in order to obtain PCl_(5) at 1 atm? (K_(p) "for dissociation of" PCl_(5)=1.78) .

Prove that the pressure necessary to obtain 50% dissociation of PCl_(5) at 250^(@)C is numerically three times of K_(p) .

For the reaction PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g) the value of K_(p) at 250^(@)C is 0.61atm ^(-1) The value of K_(c) at this temperature will be

At 250^(@)C and 1 atmospheric pressure, the vapour density of PCl_(5) is 57.9 . What will be the dissociation of PCl_(5) –