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x^(2)+10x+21=x^(2)+(.......+3)x+21 | 8 |...

x^(2)+10x+21=x^(2)+(.......+3)x+21 | 8 | बीजीय व्यंजकों का गुणनखण्डन | MATHS | STUDENTS FRIENDS ...

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x ^(2) + 4x - 21 =?

(5)/(2)x+3=(21)/(2)

(x^2-4x-21)=?

x^2-21 x+90

(i) x^(2) -10x+21 = 0 (ii) y^(2) -11y+18 = 0

Factorise the x ^(2) - 10 x + 21

Factorize: 21x^(2)-2x+(1)/(21)