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tan 30^(@).sin30^(@).cot60^(@).cosec30^(...

tan 30^(@).sin30^(@).cot60^(@).cosec30^(@)= | 10 | गणित प्रश्न पत्र (2020 A) | MATHS | BIHAR BOA...

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cot60^(@)xxtan30^(@)= ?

(tan60^@)/(sin60^@+cos30^@)

(tan60^(@)-tan30^(@))/(1+tan60^(@)tan30^(@))=tan30

"(1) "sin60^(@)cos30^(@)+sin30^(@)cos60^(@)

(sin30^(@)-sin90^(@)+2cos0^(@))/(tan30^(@)tan60^(@))

Evalutate : sin60^(@) cos 30^(@)+sin30^(@)cos 30^(@) .

Evaluate (tan60^(@)-tan30^(@))/(1+tan60^(@)tan30^(@)) .

cot30^@ - 1/2 xx cosec 60^@ =

sin30 ^ (@) sin ^ (2) (60) ^ (@) + 3cos60 ^ (@) tan45 ^ (@) =

(tan 60^(@) - tan 30^(@))/(1 + tan 60^(@) tan 30^(@)) equal