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"(3/(x^2)-(x^3)/6)^7 ના વિસ્તરણમાં ...

"`(3/(x^2)-(x^3)/6)^7` ના વિસ્તરણમાં અંતથી 4થી પદ શોધો."

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int(x^2-3)/(x^3-7x+6)dx

(2x+7)/(x-6)=(3)/(4)

(x+3)(x+4)(x+6)(x+7)=1120 .

(3)/(4)x+4x=(7)/(8)+6x-6

int(4x+6)/(x^2+3x-7)dx=?

" (a) (x-3)/(3x-4)=(2x+5)/(6x+7)

(2x-(7-5x))/(9x-(3+4x))=7/6

(5x^(2)+6x+7)/(2x^(2)+3x+4)

(2x-(7-5x))/(9x-(3+4x))=(7)/(6)

((5x^(2) + 6x+ 7))/((2x^(2) + 3x +4))

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