1500 সেমি^(3) দ্রবণে 18 গ্রাম ইউরিয়া যুক্ত ইউরিয়ার একটি জলীয় দ্রবণের ঘনত্ব 1.5...

An aqueous solution of urea containing 18 g urea in 1500 cm^(3) of solution has a density of 1.5 g//cm^(3) . If the molecular weight of urea is 60. Then the molality of solution is:

If u = 3t^(4) - 5t^(3) + 2t^(2) - 18t+4 , find (du)/(dt) at t = 1 .

An aqueous solution of urea containing 18 g urea in 1500 cm^3 of solution has a density of 1.052 g/ cm^3 . If the molecular weight of urea is 60, then the molality of solution is-

2, 3.1, 5.3, 8.6, 13, 18, 25.1

Solve : (a) 1/18+1/18 (b) 8/15 + 3/15 (c) 7/5-5/7 (d) 1/22 + (21_/(22)(e) (12)/(15) -(7)/(15) (f) 5/8 + 3/8 (g) (1) - 2/3 (1=3/3) (h) 1/4 + 0/4 (i) (3) -(12)/5

Compare and fill in the box with lt, gt or =. 18.8 + 3 ( 1)/( 5) + 7 ( 3)/( 5) square 16.2 + 4 ( 7 )/( 25) + 3 ( 1)/( 8)

Complete the following activity to solve simultaneous equations : 4x+ 3y = 18 " "...(1) 5x - 3y = 9 " " ...(2) Adding equations (1) and (2) , +{:(4x+3y=18" ...(1)"),(5x-3y=9" ...(2)"),(bar(squarex" "=square)):} :. X = (square)/(square ) " " :. X = square Substituting x = 3 in equation (1) , 4 xx square + 3y = 18 " " :. 3y = 18 - square " " :. 3y = square :. y = 2 (x,y ) = (square, square ) is the solution

Simplify: (-18 1/3 xx 2 8/11) -(4 5/7 xx 2 (1/3))