ইউরিয়ার 5% দ্রবণের জন্য (মোলার ভর - 60 গ্রাম/মোল), 300 K এ অসমোটিক চাপ গণনা করুন। [R =...

For a 5% solution of urea (Molar mass - 60 g/mol), calculate the osmotic pressure at 300 K. [R = 0.0821 L atm K^(-1) mol^(-1)]

Calculte the osmotic pressure os a solution obtained by mixing 100 mL of 4.5% solution of urea (mol. Mass =60) and 100 mL pf 3.42% solution of cane sugar (mol. Mass =342) at 300 K. (Given R=0.0821 L atm K^(-1) mol^(-1))

The decomposition of phosphine, 4PH_(3)(g) to P_(4)(g) + 6H_(2)(g) has rate law , Rate = k[PH_(3)] . The rate constant is 6.0 xx 10^(-4) s^(-1) at 300 K and activation energy is 3.05 xx 10^(5) J mol^(-1) . Calculate the value of the rate constant at 310 K ( R= 8.314 JK^(-1)mol^(-1))

A solution obtained by mixing 100 mL of 20% solution of urea (molar mass =60) and 100 mL of 1.6% solution of cane sugar (molar mass =342) at 300 K . (R=0.083 L bar K^(-1) mol^(-1) ). Calculate a.Osmotic pressure of urea solution b.Osmotic pressure of cane sugar solution c.Total osmotic pressure of solution

Study the following information carefully and answer the given questions based on it The English alphabet is categorised into five groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus group one consists of A, B, C and D, group two consists of E, F,G and H, group three consists of I, J, K, L, M and N, group four consists of O, P, Q,R, S and T, and the remaining letters make group five. These groups are assigned values as 10 for each letter of first group, 20 for each letter of second group, 30 for each letter of third group, 40 for each letter of fourth group, and 50 for each letter of group five. When used to form words, the value of each letter should be added up to compute the value of the word. If the word has letters only from the same group the value of the word would be the value of the sum of letters. However, if the letters in a word are from difierent groups, the value of the first letter of the word and any other letter of that group will be the same as that of its individual letter value of its group, but that of a letter from another group will be 'double’ as much as the value of each letter of its group. If we have to find the value of MANGO, its first letter is M (from third group), among A, N, G and O, N is also from third group. Hence value of M + N = 30 + 30 = 60 Now A, G and O belong to first, second and the fourth group respectively. Hence value of A + G + O = double the value of A + double the value of G + double the value of O = 2*10 + 2*20 + 2* 40 = 140. Hence, total value = 140+60 = 200. SOUND 1)200 2)170 3)300 4)260 5)None of these

Study the following information carefully and answer the given questions based on it The English alphabet is categorised into five groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus group one consists of A, B, C and D, group two consists of E, F,G and H, group three consists of 1, J, K, L, M and N, group four consists of O, P, Q,R, S and T, and the remaining letters make group five. These groups are assigned values as 10 for each letter of first group, 20 for each letter of second group, 30 for each letter of third group, 40 for each letter of fourth group, and 50 for each letter of group five. When used to form words, the value of each letter should be added up to compute the value of the word. If the word has letters only from the same group the value of the word would be the value of the sum of letters. However, if the letters in a word are from difierent groups, the value of the first letter of the word and any other letter of that group will be the same as that of its individual letter value of its group, but that of a letter from another group will be 'double’ as much as the value of each letter of its group. If we have to find the value of MANGO, its first letter is M (from third group), among A, N, G and O, N is also from third group. Hence value of M + N = 30 + 30 = 60 Now A, G and O belong to first, second and the fourth group respectively. Hence value of A + G + O = double the value of A + double the value of G + double the value of O = 2*10 + 2*20 + 2* 40 = 140. Hence, total value = 140+600 = 200. CONCEPT 1)70 2)150 3)360 4)300 5)None of these