Home
Class
MATHS
A steel wire 4.0m in length is stretched...

A steel wire` 4.0m` in length is stretched through `2.0mm`.The cross -sectional area

Promotional Banner

Similar Questions

Explore conceptually related problems

A steel wire 4.0 m in length is stretched through 2.0 mm. The cross-sectional area of the wire is 2.0 mm^(2) . If young's modulus of steel is 2.0 xx 10^(11) Nm^(-2) , then find the energy density of wire.

A steel wire of 4.0 m in length is stretched through 2.00 mm. The cross-sectional area of the wire is 2.0mm^(2) if young's modulus of steel is 2.0xx10^(11)N//m^(2) find (i) the energy density of wire (ii) the elastic potential energy stored in the wire.

A steel wire of length 2.0 m/s is stretched through 2.0 mm. The cross sectional area of the wire is 4.0 mm^2. Calculate the elastic potential energy stored in the wire in the stretched condition. Young modulus of steel =2.0x10^11Nm^-2

A steel wire of length 3.0m is stretched through 3.0 mm. the cross-sectional area of the wire is 5.0mm^(2) . Calculate the elastic potential energy stroed in the wire in the stretched condition. Young's modulus of steel is 2.0 xx 10^(11) Nm^(-2) .

A steel wire of 4.0 m is stretched through 2.0 mm. The cross - sectional area of the wire is 2.0 mm^2. If young's modulus of steel is 2.0 xx10^(11) Nm^(-2) find (i) the energy density of the wire, (ii) the elastic potential energy stored in the wire.

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10^(–6) m^(2) and Y is 2 xx 10^(11) N//m^(2) . Increase in length of the wire will be -

Compute the elongation of the steel wire and brass wire in the given Given unloaded length of steel wire = 2.0 m, unloaded length of brass wire = 1.0m. Area of cross-section of each wire = 0.049 cm^2. Y_(steel) = 2xx10^(11)Pa and Y_(Brass) = 0.90 xx 10^(11)P_a , g = 9.8 ms^(-2)

A Steel wire is 1m long and 1mm^(2) in area of cross-section. If it takes 200N to streach this wire by 1mm , the forces that will be required to stretch the wrie of the same material and cross-sectional area form a length of 10m to 1002cm

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)

A rod PQ of length 1.05m having negligible mass is supported at its ends by two wires one of stell (wire A ), and the other of aluminium (wire B ) of equal lengths as shown in fig. The cross-sectional areas of wires A and B are 1.0mm^(2) and 2.0mm^(2) respectively. At what point along the rod a load W be suspended in order to produce (a) equal stress, (b) equal strains in both steel an aluminium. (Y_("steel") = 200 GPa, Y_("aluminium") = 70 GPa)