`PCl_(5)` এর `2 "মোল"`কে `2 লিটার` ক্ষমতার একটি বন্ধ পাত্রে গরম করা হয়েছিল। ভারসাম্যে `40%`

PCl_(5) is 50% dissociated into PCl_(3) and Cl_(2) at 1 atmosphere pressure. It will be 40% dissociated at:

2 "mole" of PCl_(5) were heated in a closed vessel of 2 litre capacity. At equilibrium 40% of PCl_(5) dissociated into PCl_(3) and Cl_(2) . The value of the equilibrium constant is:

Two moles of PCl_(5) were heated to 327^(@)C in a closed two-litre vessel, and when equilibrium was achieved, PCl_(5) was found to be 40% dissociated into PCl_(3) and Cl_(2) . Calculate the equilibrium constant K_(p) and K_(c) for this reaction.

Pure PCl_(5) is introduced into an evacaated chamber and to equilibrium at 247^(@)C and 2.0 atm .The equilibrium gases mixure contains 40% choririne by volume . Calculate K_(p) at 247^(@)C for the reaction PCl_(5)(g)hArrPCl_(3)(G)+Cl_(2)(g)

Pure PCl_(5)(g) was introduced into an evacuated vessel and comes to equilibrium at 24^(@)C and 2 atm pressure. At equilibrium mixture contains 40% by volume of Cl_(2)(g) PCl_(5)(g)hArr(PCl_(3)(g)+Cl_(2)(g) Which of the following statement(s) regarding the above equilibrium is/are correct?