যখন `PCl_(5)` উত্তপ্ত হয়, তখন এটি `PCl_(3)` এবং `Cl_(2)`-এ বিচ্ছিন্ন হয়। বাষ্পের ঘনত্ব

Why PCl_(5) dissociates to give PCl_(3) and Cl_(2) ?

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

PCl_(5) on heating dissociates to PCl _(3) and Cl _(3) because :

PCl_(5) overset(Delta)to PCl_(3)+Cl_(2)

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :

PCl_(3) is prepared by the action of Cl_(2) on

In the reaction, PCl_(5)hArrPCl_(3)+Cl_(2) , the amounts of PCl_(5) , PCl_(3) and Cl_(2) , 2 moles each at equilibrium and the total pressure is 3 atm . Find the equilibrium constant K_(p) .